For bcc:
The body diagonal of the cube is equal to 4r, where r is the radius of the iron atom.
So, $4r = \sqrt{a^2 + a^2 + a^2}$, where a is the edge length of the cube.
Solving for a, we get $a = \sqrt{2} \cdot 2r$.
The volume of the bcc unit cell is $V_{bcc} =
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