Question

Put the following statements into order to prove the summation formula P(n) = (Ci1i= n(n+1) for all n â‰¥ 1. Put N next to the statements that should not be used: 1. The statement is true for n = 1 because in that case, both sides of the equation are 1. 2. Now suppose we have proved the statement P(n) for some n â‰¥ 1. Xi1i+(+1)-Xitii= n(n+4 + (n +1) 3. Now suppose we have proved the statement P(n) for all n > 1. 4. By adding n + 1 to both sides of P(n), we get Xi1i+(+1)=Xitli= 96+42 + (+1) 5. By adding +1 to both sides of P(n), we get 6. We simplify the right side: "(7+l + (n +1) = (n + 1)(2 +1) = (n+Jn+2) 7. Thus we have proved the statement P(n+1) = (L;+! i = (46+2) 8. The statement is true for n = 1 because in that case, both sides of the equation are 0.

          Put the following statements into order to prove the summation formula P(n) = (Ci1i= n(n+1) for all n â‰¥ 1. Put N next to the statements that should not be used:
1. The statement is true for n = 1 because in that case, both sides of the equation are 1.
2. Now suppose we have proved the statement P(n) for some n â‰¥ 1. Xi1i+(+1)-Xitii= n(n+4 + (n +1)
3. Now suppose we have proved the statement P(n) for all n > 1.
4. By adding n + 1 to both sides of P(n), we get Xi1i+(+1)=Xitli= 96+42 + (+1)
5. By adding +1 to both sides of P(n), we get
6. We simplify the right side: "(7+l + (n +1) = (n + 1)(2 +1) = (n+Jn+2)
7. Thus we have proved the statement P(n+1) = (L;+! i = (46+2)
8. The statement is true for n = 1 because in that case, both sides of the equation are 0.

put the following statements into order to prove the summation formula pn ci1i nn1 for all n 2 1 put n next to the statements that should not be used 1 thus we have proved the statement pn1 13744

Added by Noelia R.

Question

Please give Ace some feedback