Question

A helical compression spring made of oil tempered carbon steel, is subjected to a load which varies from 500 N to 1000 N. The spring index is 6 and the design factor of safety is 1.25. For calculation purpose consider the yield stress in shear is 770 MPa and endurance stress in shear is 350 MPa, compression of the spring at the maximum load is 30 mm and modulus of rigidity for the spring material is 80 GPa. find : (a) Size of the spring wire, (b) Diameters of the spring, (c) Number of turns of the spring, and (d) Free length of the spring.

          A helical compression spring made of oil tempered carbon steel, is subjected to a load which varies from 500 N to 1000 N. The spring index is 6 and the design factor of safety is 1.25. For calculation purpose consider the yield stress in shear is 770 MPa and endurance stress in shear is 350 MPa, compression of the spring at the maximum load is 30 mm and modulus of rigidity for the spring material is 80 GPa. find :

(a) Size of the spring wire,
(b) Diameters of the spring,
(c) Number of turns of the spring, and
(d) Free length of the spring.

Show more…

A helical compression spring made of oil tempered carbon steel, is subjected to a load which varies from 500 N to 1000 N. The spring index is 6 and the design factor of safety is 1.25. For calculation purpose consider the yield stress in shear is 770 MPa and endurance stress in shear is 350 MPa, compression of the spring at the maximum load is 30 mm and modulus of rigidity for the spring material is 80 GPa. find :

(a) Size of the spring wire,
(b) Diameters of the spring,
(c) Number of turns of the spring, and
(d) Free length of the spring.

Added by Michael H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Lien Le

10/15/2024

Step 1

Given the spring index \( C = 6 \), the spring index is defined as: \[ C = \frac{D}{d} \] where \( D \) is the mean diameter of the spring and \( d \) is the wire diameter. Rearranging for \( D \): \[ D = C \cdot d = 6d \] Show more…

Show all steps

lock

Thanks for your feedback!

A helical compression spring made of oil tempered carbon steel, is subjected to load which varies from 500 N to 1000 N. The spring index is 6 and the design factor of safety is 1.25. For calculation purpose consider the yield stress in shear is 770 MPa and endurance stress in shear is 350 MPa, compression of the spring at the maximum load is 30 mm and modulus of rigidity for the spring material is 80 GPa. find Size of the spring wire; Diameters of the spring; Number of turns of the spring; and Free length of the spring:

Play audio

Feedback

Powered by NumerAI

Lien Le and 73 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later