00:04
So in this problem here, the first thing we have to do is labor will be doing now.
00:16
So from our table, the torso property is the fillet, from the fillet, our throat area, a, is equal to one point, 1 .14, times the height, times the diameter.
00:48
Substituting our height in our day.
00:51
In our diameter, we have 1 .44 times 6 times 40.
01:07
That is equal to 33936.
01:25
Now we can calculate the primary stress, which is equal to v over a.
02:04
Where v is the force so now, we have f times 1 ,000 divided by the area, which is 339 .36.
02:56
And that gives us 2 .946.
03:24
So the next step, we have to obtain the formula from our table.
03:29
So according to the torsional properties of the fillet whales, the unit's second polar coordinate i .m.
03:43
Is equal to the distance times 3b squared plus d squared all over 6.
04:21
So this gives us 40, 40 times 3 times 40 squared plus 40 squared divided by 6.
04:44
And we get i -sum -n to be equal to 4 -2 -6666 .6 meter squared.
05:06
So the formula for the second polar moments of our area, that is 0 .707 times the height times the moment area, i .s .m...