0:00
Hi there.
00:01
So for this problem, we are told that an alternative approach to the to calculate the translational partition function is over all possible position and momentum vectors.
00:17
So in this case, we need to calculate that by evaluating the integrals explicitly and to show that this expression yells the same.
00:30
Same result for the translational partition function as that obtained in the task.
00:36
Now, in here, we know that because the translational kinetic energy does not depend on position, the integral is independent of the position, and therefore, of the integral over this is going to produce a factor of the volume.
00:59
Now, the momentum integrals can be evaluated either in rectangular, or this vertical coordinates.
01:05
Now, choosing rectangular coordinates, we have that the translational energy is equal to the x component of the momentum squared divided by two times the mass, plus the y component of the momentum squared divided by two times the mass, plus the seed component of the momentum divided by two times the mass...