Question

Q 30cm 20cm 10cm F=8000N 20cm 100cm Find if any of the webs buckle in the box beam shown. $t_{web} = 2mm, E=70 GPa,$ $A_{stiff} = 5 cm^2$ (for all) critical stresses for buckling $\sigma_{cr (compr)} = 3.62E(\frac{t}{b})^2$ $\tau_{cr} = 4.8E(\frac{t}{b})^2$ $\sigma_{cr (bending)} = 22E(\frac{t}{b})^2$

Name: q 30cm 20cm 10cm f8000n 20cm 100cm find if any of the webs buckle in the box beam shown tweb 2mm e70 gpa astiff 5 cm2 for all critical stresses for buckling sigmacr compr 362efractb2 tau 50076
Uploaded: 2023-12-14T07:51:43-08:00
Duration: 2 min 42 s
Channel: Supreeta N
Description: q 30cm 20cm 10cm f8000n 20cm 100cm find if any of the webs buckle in the box beam shown tweb 2mm e70 gpa astiff 5 cm2 for all critical stresses for buckling sigmacr compr 362efractb2 tau 50076

          Q
30cm
20cm
10cm
F=8000N
20cm
100cm
Find if any of the webs buckle
in the box beam shown.
$t_{web} = 2mm, E=70 GPa,$
$A_{stiff} = 5 cm^2$ (for all)
critical stresses for buckling
$\sigma_{cr (compr)} = 3.62E(\frac{t}{b})^2$
$\tau_{cr} = 4.8E(\frac{t}{b})^2$
$\sigma_{cr (bending)} = 22E(\frac{t}{b})^2$

$q 30cm 20cm 10cm f8000n 20cm 100cm find if any of the webs buckle in the box beam shown tweb 2mm e70 gpa astiff 5 cm2 for all critical stresses for buckling sigmacr compr 362efractb2 tau 50076$

Added by Francisca A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

12/14/2023

Step 1

The problem asks to determine if any of the webs in the box beam will buckle. We are given the dimensions of the box beam, the web thickness ($t_{web}$), the Young's modulus ($E$), and the stiffener area ($A_{stiff}$). We are also provided with formulas for Show more…

Show all steps

Thanks for your feedback!

Q 30cm 20cm 10cm F=8000N 20cm 100cm Find if any of the webs buckle in the box beam shown. $t_{web} = 2mm, E=70 GPa,$ $A_{stiff} = 5 cm^2$ (for all) critical stresses for buckling $\sigma_{cr (compr)} = 3.62E(\frac{t}{b})^2$ $\tau_{cr} = 4.8E(\frac{t}{b})^2$ $\sigma_{cr (bending)} = 22E(\frac{t}{b})^2$