00:01
In part a, we would like to find the steady -state amplitude at resonant frequency.
00:07
So here we have q is equal to the square root of omega -squared minus r -squared divided by 2 -pil, 2m -l, where r is our damping coefficient.
00:19
Here, r is equal to b, so q is equal to omega -squared minus b -squared divided by 2m squared.
00:30
So we get q is equal to omega.
00:32
At resonance, the amplitude is maximum, so q is omega.
00:37
So our amplitude, a -max, is equal to f -0 divided by m times square root of omega -squared minus omega -squared, squared, plus r -squared omega -squared divided by m -squared.
00:51
So we get f -0 divided by r -o -m -m, but r is equal to b, so our a -max is f -0 divided by b times omega.
01:01
Our a max, so our omega is 5 radiance per second.
01:07
Our b is 60 and our f0 is 48...