Question

Q. No. 2. Write a C++ code using nested FOR loops to create an odd number i.e. n x n (e.g. 5x5) matrix implementing the following rules. 1. Place first number (1) in the middle cell to start. 2. For placing each next number: (i) Increment number by 1, increment column by 1 and decrement row by 1. (ii) If you are in the last column, then go to the first column in the same row and decrement row by 1 and place the number if cell is empty. (iii) If you are in the first row, then go to the last row in the same column and increment column and place the number if cell is empty. (iv) If the target cell already has a number, then go back to the immediate previous empty cell in the same order and hierarchy and place the number. (v) Sample output is as shown in Fig. 4. \begin{array}{|c|c|c|c|c|} \hline 0 & 1 & 2 & 3 & 4 \\ \hline 0 & 9 & 15 & 16 & 22 & 3 \\ \hline 1 & 14 & 20 & 21 & 2 & 8 \\ \hline 2 & 19 & 25 & 1 & 7 & 13 \\ \hline 3 & 24 & 5 & 6 & 12 & 18 \\ \hline 4 & 4 & 10 & 11 & 17 & 23 \\ \hline \end{array} Fig. 4

          Q. No. 2. Write a C++ code using nested FOR loops to create an odd number i.e. n x n (e.g.
5x5) matrix implementing the following rules.
1. Place first number (1) in the middle cell to start.
2. For placing each next number:
(i) Increment number by 1, increment column by 1 and decrement row by 1.
(ii) If you are in the last column, then go to the first column in the same row
and decrement row by 1 and place the number if cell is empty.
(iii) If you are in the first row, then go to the last row in the same column and
increment column and place the number if cell is empty.
(iv) If the target cell already has a number, then go back to the immediate
previous empty cell in the same order and hierarchy and place the number.
(v) Sample output is as shown in Fig. 4.
\begin{array}{|c|c|c|c|c|}
\hline
0 & 1 & 2 & 3 & 4 \\
\hline
0 & 9 & 15 & 16 & 22 & 3 \\
\hline
1 & 14 & 20 & 21 & 2 & 8 \\
\hline
2 & 19 & 25 & 1 & 7 & 13 \\
\hline
3 & 24 & 5 & 6 & 12 & 18 \\
\hline
4 & 4 & 10 & 11 & 17 & 23 \\
\hline
\end{array}
Fig. 4

Q. No. 2. Write a C++ code using nested FOR loops to create an odd number i.e. n x n (e.g.
5x5) matrix implementing the following rules.
1. Place first number (1) in the middle cell to start.
2. For placing each next number:
(i) Increment number by 1, increment column by 1 and decrement row by 1.
(ii) If you are in the last column, then go to the first column in the same row
and decrement row by 1 and place the number if cell is empty.
(iii) If you are in the first row, then go to the last row in the same column and
increment column and place the number if cell is empty.
(iv) If the target cell already has a number, then go back to the immediate
previous empty cell in the same order and hierarchy and place the number.
(v) Sample output is as shown in Fig. 4.

0 1 2 3 4

0 9 15 16 22 3

1 14 20 21 2 8

2 19 25 1 7 13

3 24 5 6 12 18

4 4 10 11 17 23

Fig. 4

Added by John K.

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