b. $_6P_2$ c. number of arrangements in a row of 7 objects taken 2 at a time d. $_8P_3$ e. number of arrangements in a row of 10 objects taken 4 at a time f. $_{12}P_7$
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Step 1
This can be calculated using the formula for combinations, which is nCr = n! / (r!(n-r)!), where n is the total number of objects and r is the number of objects taken at a time. In this case, n = 7 and r = 2. Plugging these values into the formula, we get: 7C2 = Show more…
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