Q1 a brass alloy is known to have a yield strength of 275...

Transcript

00:01 In this question they given the so the questions so the question now we have to find out so answer to the given question here so now let come to the answer for this question that is solution so here first we will calculate the first we will calculate the so the strain at the yielding so at the yielding yielding that which using the so yield strength here so which is given the question so after that so after that we will calculate the strain so we will calculate the strain so calculate the strain and the test so which is on the so on the test so on the test specimen so which is given as so if that is e test so less than the e of yield here so in this case so that is in this case elastic deformation so that is elastic deformation elastic deformation so takes place take place and we can calculate the so in this position we can calculate the load so here is the load and if so here is the condition that e of test which is greater than e of yield here so here in this this position we cannot calculate the so which is implied we cannot so find out the find out the load due to plastic deformation so why because due to plastic deformation so come also we don't have stress we don't have stress so that is stress so that is here so plot so that is given as the from the given information dimension that is e of test which is equal to delta 1 divided by 10 so and this value is equal to 2 .0 mm which is divided by thousand here so that is equal to this value became a 2 .0 which is multiplied by the so 10 power minus 3 that is equal to the value is 0 .002 here so in the same way so e of yield here so that is equal to here sigma y which is divided by e that is equal to 275 divided by so 1 or 3 which is multiplied by the 10 cube here and this whole value is equal to we can write as a 2 .66 which is multiplied by the 10 power minus 3 and this value is becoming 0 .00 to double 6 here.

05:43 So in this case, so based on this values here, so as e -test, which is less than e -yield, so we can find, so we can find out the magnitude of the load so the magnitude of the load so from this information now we have to find out the load here let come to that so that now we are using here so now using that is magnitude p is equal to here s1 divided by l which is multiply by the e and multiply by the ac here.

06:49 So from the given information and above information we know the values of these terms.

06:55 That is here s1 is equal to 2 mm comma l is equal to thousand and e is equal to so one or three so one or three gp and that is equal to this value is equal to this value is equal to to here one or three which is multiplied by the 10 power 9 so n divided by m square so that 1 so 1 n divided by m m square that is equal to the value is 1 3 which is multiply by the so this is in n divided by m m square so and under 1 ac is equal to pi divided by 4 which is multiply by the d square that is equal to pi divided by four and which is multiplied by the so here the deval value from the above information 12 .7 whole square and this value is became a 126 .67 mm square so that now we know the all the values of these terms now have to substitute these values in the abo equation so that is equal to p is equal to 2 which is divided by thousand and multiply by the so 1 or 3 which is multiplied by the 10 cube and multiply by the 126 .67 and p is equal to here 26094 .0 to n so and this value is becoming finally that is p is equal to 26 .09 here...

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