Q1 a projectile has an initial velocity of 80 m sec at an...

'Q1/ A projectile has an initial velocity of 80 m / sec at an angle of 53 above the horizontal: Calculate (a) the horizontal distance from the starting point three seconds after it is fired, (b) the vertical distance above the starting point at the same time, and (c) the horizontal and vertical components of its velocity at this time_'

Transcript

00:01 In the given question, we are supposed to find the horizontal distance, vertical distance from starting point in the horizontal and vertical components.

00:07 So first of all we are given initial velocity, initial velocity which is equal to 80 meter per seconds, 80 meters divided by seconds.

00:20 And angle of projection we are given which is equal to 53 degree.

00:24 So now for the part a we would solve.

00:27 So we are given time is equal to 3 seconds.

00:31 So now considering the horizontal component we have according to the second law kinematics we know that s is equal to u t plus half 80 square and this would become zero as we know that a is equal to zero so we can say as x component is equal to ux t so we can say s x would be equal to u cost theta t so we can say this would be 30 that is already 80 i'm sorry for this 80 cost 53 multiplied by we have three seconds over here now now when we solve this we have 30 80 multiplied by cost 53 multiplied by 3 we know cost 53 is 3 divided by 5 multiplied by 3 so this 5 when we cancel out this we have 1 and 16 so 16 multiplied by 9 would be equal to so s x would be equal to 144 now for the b part we have for the b part this is the answer for a part then for the b part we are given that we are supposed to find for the vertical distance so we would consider s y which is equal to uy t minus r gt square and now we have 80 uyt would be 80 cause of uh of 50 sign of 53 degree so sign of 53 degree would be 4 divided by 5 so we would right here 4 divided by 5 then minus of half gt square which is 9 point we can say this would be 9 .81 multiplied by 3 so when we solve this we get 5 would be 16 16 4za we have 16 4 is 64 so this would be equal to 64 minus of 9 .81 1 so 9 .81 multiplied by 3 is 29 .43.

02:42 So 29 .4.

02:44 So, 64 minus 29 .4 .3 would be equal to 34 .57.

02:53 So this is the answer for second part...

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