00:01
Given the value of kb equals to 1 .5 and kt equals to 1 .2.
00:12
To draw the following diagram, this is the value of c.
00:31
Here the value is 680 newton and the point is a, the point here is d, the point here is b and the value is 212 .13.
00:53
This is 200, the value here is 300 and the value here is 200.
01:04
This point is represented as c and this as d.
01:18
This point is represented as a and its value is 64 .63 nm.
01:27
This is 42 .426 nm and this is also 42 .426 nm.
01:52
Proceeding further, for the bending moment diagram, it can be drawn as this which is 48 nm and this which is 3 nm.
02:25
We can write this as torque diagram.
02:39
To calculate the relative forces vertically equals to 165 plus 135 multiplied with sin 45 that is equals to 212 .13 nm.
03:12
Proceeding further, we have to calculate the vertical forces bending moment and the given equation is minus 680 multiplied with 200 plus r0 multiplied with 500 minus 212 .13 multiplied with 700 equals to 0.
04:01
Thus the value of r0 equals to 568 .98 nm.
04:14
Also summation of md equals to 0.
04:21
So the equation is minus rc multiplied with 500 plus 680 multiplied with 300 minus 212 .13 multiplied with 200 equals to 0.
04:43
Thus the final value of rc equals to 323 .148 nm...