00:01
Hello students, according to the given question, from given data, from the given data, in the a bit in the question 1 to find the class interval i .e.
00:15
I is equal to l minus s is divided by 1 plus 3 .22 log n base 10.
00:24
So, by substituting, we get 52 minus 21 divided by 1 plus 3 .22 log 30 base 10.
00:36
So, that is equal to 5 .25 approximately i is equal to 5.
00:42
So, then the class and the tally marks and the frequency values and the less than cumulative frequency values and more than cumulative frequency values.
00:59
So, the class interval is 5.
01:02
So, 20 to 25, 25 to 30, 30 to 35, 35 to 40, 40 to 45, 45 to 50 and 50 to 55.
01:20
So, here it is 4, 3, 5 and 3, 3, 3, 5 and 1, here it is 3.
01:35
So, that means, the frequency is 4, 3, 8, 3, 3, 6, 3.
01:43
So, the total frequency is 30.
01:46
Here the cumulative frequency of less than type that is 4, 7, 15, 18, 21, 27 and 30.
01:57
Here the greater than frequency that means from below to high that is 3, 9, 12, 15, 23, 26 and 30.
02:10
So, this is the complete table.
02:14
So, this is the required histogram for the given data and this is the frequency polygon...