00:01
This question we have given a number minus of 1 ,13, which we have to convert first in binary 8 -bit number, and then we have to represent it as, in the first part, we have to represent it as sine magnitude number.
00:24
So first of all, let us convert this number into binary.
00:28
So for that, i need to use the division method.
00:32
That is, i will divide it by two here.
00:36
So, two five, the ten, two six, that well, remaining is one.
00:40
Two, two, eight, the sixteen, remaining is zero.
00:45
Two one's a two, four, eight, remaining is zero.
00:48
Two, seven, the fourteen, remaining zero.
00:51
Two, three, six, remaining one.
00:55
Two, one's a two, remaining is one...