Question

IPv4 Subnetting For the following exercises, come up with the subnet address, broadcast address, the number of possible hosts, and the first and last valid host address of that subnet. Example 1: 172.16.37.186/26 Subnet Mask 255.255.255.192 Subnet Address 172.16.37.128 Broadcast Address 172.16.37.191 Number of Hosts 62 First Host Address 172.16.37.129 Last Host Address 172.16.37.190 Questions: Q1: 192.168.74.210/28 Subnet Mask 02: 156.54.78.124/22 Subnet Address Broadcast Address Number of Hosts First Host Address Last Host Address Subnet Mask Subnet Address

          IPv4 Subnetting
For the following exercises, come up with the subnet address, broadcast address, the number
of possible hosts, and the first and last valid host address of that subnet.
Example 1:
172.16.37.186/26
Subnet Mask
255.255.255.192
Subnet Address
172.16.37.128
Broadcast Address
172.16.37.191
Number of Hosts
62
First Host Address
172.16.37.129
Last Host Address
172.16.37.190
Questions:
Q1:
192.168.74.210/28 Subnet Mask
02:
156.54.78.124/22
Subnet Address
Broadcast Address
Number of Hosts
First Host Address
Last Host Address
Subnet Mask
Subnet Address

Show more…

IPv4 Subnetting
For the following exercises, come up with the subnet address, broadcast address, the number
of possible hosts, and the first and last valid host address of that subnet.
Example 1:
172.16.37.186/26
Subnet Mask
255.255.255.192
Subnet Address
172.16.37.128
Broadcast Address
172.16.37.191
Number of Hosts
62
First Host Address
172.16.37.129
Last Host Address
172.16.37.190
Questions:
Q1:
192.168.74.210/28 Subnet Mask
02:
156.54.78.124/22
Subnet Address
Broadcast Address
Number of Hosts
First Host Address
Last Host Address
Subnet Mask
Subnet Address

Added by James G.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Mohan Jain

Step 1

For the first example, the IP address is 156.54.78.124/22. This means that the first 22 bits are the network address and the remaining 10 bits are for host addresses. The network address is obtained by setting all the host bits to 0. So, the network address is Show more…

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Q1 Questions: Example 1 IPv4 Subnetting 156.54.78.124/22 192.168.74.210/28 172.16.37.186/26 Subnet Address: 172.16.37.128 Subnet Mask: 255.255.255.192 First Host Address: 172.16.37.129 Last Host Address: 172.16.37.190 Number of Hosts: 62 Broadcast Address: 172.16.37.191 Subnet Address: 192.168.74.208 Subnet Mask: 255.255.255.240 First Host Address: 192.168.74.209 Last Host Address: 192.168.74.222 Number of Hosts: 14 Broadcast Address: 192.168.74.223 Subnet Address: 156.54.78.0 Subnet Mask: 255.255.252.0 First Host Address: 156.54.78.1 Last Host Address: 156.54.81.254 Number of Hosts: 1022 Broadcast Address: 156.54.81.255

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