00:01
Hello students, let's solve this problem.
00:02
The problem says the first question is given that a circle is defined by the equation.
00:10
X square plus of y square is equal to 196.
00:17
State the coordinates of the center.
00:21
You have to find out the center and the radius of the circle.
00:29
That we want to find out.
00:32
So for this problem, you have to know that what is the form of the circle is x minus x1 square, y minus y1 square is equal to r square, so that the center is x1 comma y1 and radius is equal to earth.
00:58
So for this problem, we have to write down the equation as x minus 0 whole square, y minus 0 whole square is equal to 14 square.
01:12
So what is the center for this problem? center is 0 .0 and radius is equal to 14 unit.
01:24
So this is the answer for the first question that the center and the radius of this given problem, radius and the center.
01:44
And we move to the second problem that is given that the lying segment ab whose end points a is given here minus 4 .3.
01:57
And b is given here 2 comma of 7.
02:02
So find the equation of the line parallel to a, b and passing through the point, passing through 4 comma minus 2.
02:20
That is the problem, that is the second problem.
02:23
So at first you have to understand that one of the line is there that the points is a and of b.
02:32
So both the points of this line segment.
02:35
So the equation that the equation is y minus y1 is equal to m x minus of x1 that is so we have to solve this problem.
02:51
So the equation can be written as that is of y minus of three.
02:59
So what is m? m is 7 minus of 3 2 plus of 4 and what we have to write down that is of x plus of 4 so after calculating this we get y minus of 3 is equal to 4 divided by this 1 is 6 x plus of 4 so that we get so that the equation we get here so the equation of the line y is equal to 2x plus of 30 that is the equation of the line so now the slope slope of ab that is is equal line is parallel to ab hence the slope will be same so we can say that that the slope is same.
04:07
So general form of the equation is equal to m y is equal to mx plus of c.
04:14
So we put those points that is y is equal to 2x plus of c.
04:21
So now this is passing through, so passing through the point of 4 comma minus 2.
04:29
So then we put those values that is minus 2 is equal to 8.
04:34
Plus c so c is equal to minus 10 so the equation is y is equal to 2x minus of 10 so this is the equation answer of the second question now we move to the third question that is the question number c is given determine the equation of the circle with the diameter that is end point a is minus 8 .50 and of b, 8 .15, that is given.
05:16
So we have to solve this problem of question number c.
05:20
That is a circle...