Question

Q10. Let $y$ = petal length, $x_1$ = sepal length, and $x_2$ = petal width. Consider the following R output: Call: lm(formula = Petal.Length ~ Sepal.Length + Petal.width + Sepal.Length * Petal.width, data = iris) Residuals: Min 1Q Median 3Q Max -0.99588 -0.24329 0.00355 0.29735 1.24780 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) -3.24804 0.59586 -5.451 2.08e-07 * Sepal.Length 0.87551 0.11667 7.504 5.60e-12 * Petal.width 2.97115 0.35836 8.291 6.74e-14 * Sepal.Length:Petal.width -0.22248 0.06384 -3.485 0.00065 * --- Signif. codes: 0 ‘’ 0.001 ‘’ 0.01 ‘’ 0.05 ‘.’ 0.1 ‘ ’ 1 Residual standard error: 0.3888 on 146 degrees of freedom Multiple R-squared: 0.9525, Adjusted R-squared: 0.9515 F-statistic: 975.4 on 3 and 146 DF, p-value: < 2.2e-16 (a) Write the equation of the estimated regression line. (b) The error sum of square is $SSE = 22.06596$. Estimate $\sigma$. (c) Calculate a point prediction for sepal length, when sepal length is 4.6 and petal width is 0.2.

          Q10. Let $y$ = petal length, $x_1$ = sepal length, and $x_2$ = petal width. Consider the following R output:
Call:
lm(formula = Petal.Length ~ Sepal.Length + Petal.width + Sepal.Length *
Petal.width, data = iris)
Residuals:
Min      1Q  Median      3Q     Max 
-0.99588 -0.24329  0.00355  0.29735  1.24780 
Coefficients:
            Estimate Std. Error t value Pr(>|t|)    
(Intercept)    -3.24804    0.59586  -5.451 2.08e-07 ***
Sepal.Length    0.87551    0.11667   7.504 5.60e-12 ***
Petal.width     2.97115    0.35836   8.291 6.74e-14 ***
Sepal.Length:Petal.width -0.22248    0.06384  -3.485 0.00065 ***
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 0.3888 on 146 degrees of freedom
Multiple R-squared:  0.9525,	Adjusted R-squared:  0.9515
F-statistic: 975.4 on 3 and 146 DF,  p-value: < 2.2e-16
(a) Write the equation of the estimated regression line.
(b) The error sum of square is $SSE = 22.06596$. Estimate $\sigma$.
(c) Calculate a point prediction for sepal length, when sepal length is 4.6 and petal width is 0.2.

q10 let y petal length x1 sepal length and x2 petal width consider the following r output call lmformula petallength sepallength petalwidth sepallength petalwidth data iris residuals min 1 52421

Added by Alvaro Y.

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