00:01
In this question, here we have this is our block which is situated on the inclined plane which makes an angle theta with the horizontal.
00:10
So let's first draw all the forces on the which acts on this block.
00:15
So we can write down the free body diagram for the given situation.
00:22
So as we can see, this is our fee body diagram for the given block.
00:28
Okay now let's write down all the values which are given in our equation so first we have a force which is equals to 200 newton then we have angle which is theta which is then we have the value of mass m which is equals to 15 kg next we have a g we can write it as 9 .8 meter per second square and the a which is equals to 25 centimeter per second square now using this value we can simplify this forces so let's first write down the force on the x -axis so all summation of the all the forces it becomes f cost theta minus frictional force f f f minus m g minus m g sine theta.
01:35
This is our first equation.
01:37
Now according to the newton second law, we can write this as ma.
01:41
So it becomes ma, which is equals to f cos theta minus fk minus m g sine theta.
01:52
Now let's make the equation for the fk frictional force.
01:57
So we can write fk, which is equals to f.
02:03
Cos theta minus mg sine theta minus ma.
02:10
Now we have all the values.
02:13
So let's substitute this values to get the value of a frictional force...