00:01
Good day, the topic is about pascal's principle.
00:04
According to pascal's principle, the pressure change at any point in a confined and compressible fluid is transmitted throughout the fluid such that the same change occurs everywhere.
00:16
Or to simply put it, the pressure at this point, say point a, at one section of the fluid is the same, is equal in pressure.
00:30
With the other point or on the other section of the same fluid at the same level.
00:39
With this principle, we will solve the given problem where you have a hydraulic lip that supports a certain car which weight is 12 ,000 newton that's placed at a wider arm of the lift which radius is 18 centimeters so basically this is that part here this radius right here is see is 18 centimeter now it is going to be lifted by flying force f1 at the narrower arm of the lift which radius is 5 centimeter so we wish to find how much force needs to be exerted in order to support the said car so flying pascal's principle since the pressure at point one needs to be equal to pressure at point two as the same pressure is transmitted for both for those two points at the same level then we can have it as the ratio of the force at one over the area and the area at one force of two over the area so recall that pressure is solved as the force divided by the area which is can treat the area as the cross -sectional area of the platform that supports the that supports the car and as well as the the force or the platform where you apply the pleasure so that cross -sectional area is a circular which area is solved as five times the ratios squared so you have f1 over five times r1 squared your f2 is the weight that will support over by r2 square.
02:39
So simply we can cancel the pie.
02:42
And so we have f1 rearranging...