Q11 In a CASCADE Loop, which controller should be the slower of the two? (1 mark) Q12 Does a FEED FORWARD controller have PID settings? (1 mark) Q13 Explain how you could do a level control loop, by making use of the FEED FORWARD philosophy. (4 marks) Q14 In order to combine FEEDFORWARD and FEEDBACK control, one needs to be careful. The PID Controller is easy, as it requires PID settings. The FEED FORWARD section requires something else. Please research this and provide an in-depth explanation of what you would do. (5 marks) Q15 Discuss typical ALARM PRIORITY bands. (4 marks) Q16 How does a self-tuning controller operate? (3 marks) Q17 In CASCADE control, some systems will request that you select one of three different equations. a) Explain what is meant by EQUATION A, how it is represented graphically, and where it can be utilized. (3 marks) b) Explain what is meant by EQUATION B, how it is represented graphically, and where it can be utilized. (3 marks) c) Explain what is meant by EQUATION C, how it is represented graphically, and where it can be utilized. (3 marks) (9 marks) Q18 The Process Variable jumps around, quite a bit. Which of the PID settings should we not be using, to improve controllability, and extend the life of our Final Control Element? (2 marks) A18 Student answer
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This is because the secondary controller needs to respond to changes in the setpoint from the primary (or master) controller, and if it is too fast, it may cause instability in the system. A12: A feedforward controller does not have PID settings. This is because Show more…
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A cascade control configuration is sometimes used to separate different objectives of feedback control. For instance, first an inner loop can be used to stabilize the process, and then an outer loop can be used to control the output to track set-point changes and reject disturbances. An example of a cascade control system is shown in Fig. E16.6. The process transfer function Gp(s) = (s + 1) / (s - 3) is unstable. (a) Determine the maximum range of Kinner values for which the inner loop will be stable. (b) Now assume Kc2 = 6 and Gcl is a PI controller with gain Kc1 and Ti. Find values of Kc1 and Ti such that the closed-loop poles of the transfer function from Ysp to Y(s) are at s = -0.5 ± 0.2j.
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1) Consider a feedback system with the following open loop transfer function: K(s+1)^2 G(s)H(s) = s^2((s+2)^2, K > 0 a) Sketch the root locus. Make sure to indicate the asymptote(s) and saddle points. (You are not asked to indicate all its particulars, but the ones which are asked. Otherwise, your sketch must have correct features) Prove that the point -2+j2 cannot be on the root locus. c) Consider the following controller options: P-Controller PD-Controller PI-Controller Lag compensator with the smallest a Lead compensator with the largest a i. Discuss the possible use of each choice and decide whether it can be used or not as a controller to locate one of the closed-loop poles at -2+j2. ii. Design all the suitable selections in part (i) as the controller such that they will also provide an additional steady-state gain of approximately 9 if the value of K in the uncompensated open-loop transfer function G(s)H(s) is 1. (It may or may not be possible. If it is not possible, explain why). You can use any design approach you want (analytical or empirical). iii. Could the designs in part (ii) be repeated for an additional gain of 18? Do not repeat them, just explain your reasoning.
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