00:01
For this question, solution here is, here from the above figure that here this is the charge 1, this is the charge 2 and this is the charge 3.
00:13
Here 3 charges is given making the angle 60 degree.
00:17
Here from the charge 1, here the force f2 to the charge q2 and this is the energy e3 to the charge 3 and the force f3.
00:32
Here on first charge, the charge is 1 nano coulomb.
00:36
On charge 2nd here, this is minus 2 nano coulomb and on the charge 3rd, there is minus 2 nano coulomb also.
00:45
Now for the e part, here the electrical force on q1 due to q2, here electric force on charge q1 due to charge q2, here f2 is equal to k multiply to q1 multiply to q2 divided by r.
01:11
Now substituting the value, here f1 is equal to 4 .5 multiply to 10 to the power minus 5 newton in the direction shown above.
01:25
Now the force on charge q1 due to charge q3, here this is force 3 is equal to k multiply to q1 multiply to q3 divided by a square.
01:41
Now from this, here we know that 4 .5 multiply to 10 to the power minus 5 newton.
01:49
Now in the direction shown in the diagram.
01:52
Now here we know that the total force, the net force, here it is f2 plus f3 multiply to sin 60.
02:05
Now from this, here we get that 7 .8 multiply to 10 to the power minus 5 newton.
02:15
Now by further solving for the b part, here the electric force at q1 due to q2, here it is e2 is equal to k multiply to q2 divided by a square which is equal to here 4 .5 multiply to 10 to the power 4 volt per meter in the direction shown in the figure.
02:41
Here q3 is also equal in magnitude but its own direction is shown...