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Text: Q.15 Suppose the galvanic cell sketched below is powered by the following reaction: Zn(s) + Pd(NO3)2(aq) -> Zn(NO3)2(aq) + Pd(s) S1 Write a balanced equation for the half-reaction that happens at the cathode of this cell. [1 Write a balanced equation for the half-reaction that happens at the anode of this cell. 0 0,.. e Of what substance is E1 made? 0 X G Of what substance is E2 made? 0 What are the chemical species in solution S1? 0 What are the chemical species in solution S2? 0

          Text: Q.15
Suppose the galvanic cell sketched below is powered by the following reaction:
Zn(s) + Pd(NO3)2(aq) -> Zn(NO3)2(aq) + Pd(s)

S1
Write a balanced equation for the half-reaction that happens at the cathode of this cell.
[1
Write a balanced equation for the half-reaction that happens at the anode of this cell.
0
0,..
e
Of what substance is E1 made?
0
X
G
Of what substance is E2 made?
0
What are the chemical species in solution S1?
0
What are the chemical species in solution S2?
0
        
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q15 suppose the galvanic cell sketched below is powered by the following reaction znspdno3aq znno3aqpds s1 write a balanced equation for the half reaction that happens at the cathode of this 10164

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Text: Q.15 Suppose the galvanic cell sketched below is powered by the following reaction: Zn(s) + Pd(NO3)2(aq) -> Zn(NO3)2(aq) + Pd(s) S1 Write a balanced equation for the half-reaction that happens at the cathode of this cell. [1 Write a balanced equation for the half-reaction that happens at the anode of this cell. 0 0,.. e Of what substance is E1 made? 0 X G Of what substance is E2 made? 0 What are the chemical species in solution S1? 0 What are the chemical species in solution S2? 0
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Transcript

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00:01 Okay, so we are told that we have a galvanic cell and i'm going to write the chemical equation that we're given here okay, so this is what's happening here and we are asked to a write the balanced half reaction for the cathode balanced half reaction for the cathode so my cathode will be this side my anode will be this side because this is the way they're telling me the electrons are flowing in the diagram let me go verify this because i want to make sure yes, we're given that this is the electron flow okay hang on here so our electrons are flowing from the anode to the cathode...
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