00:01
Part of this question we're going to be looking at the mean.
00:03
Now the mean is going to be the sum of all the terms divided by the number of all the terms, which in this case is 36 .75 divided by 15 and we are getting a 2 .4.
00:19
Then moving on to the next part, this is part a.
00:22
Moving on to the next part, we were looking at the standard deviation.
00:26
This would be the square root of the sum of the i minus d divided by and minus one remember this must be raised to the power of two so this is actually equal to the square root of 313 .7742 divided by one four and this would give us a 4 .7 3 .7 3.
00:50
Let me move on to determining the degrees of freedom which in this case is 15 minus 1 which gives us 14.
00:57
Then we are looking at a t value at a 0 .05 significance level, which would be 1 .761.
01:05
We now have everything to write out our confidence interval, which would be 2 .45 plus or minus, this 1 .76, multiplied by 4 .73 divided by the square root of 15, looking at 2 .15...