Question

Q2) [40p] Given the following message and carrier signal $m(t) = \cos 2000\pi t + 2\cos 6000\pi t + \cos 10000\pi t$ $c(t) = 20 \cos 320000\pi t$ a) Determine the Hilbert transform of $m(t)$. b) Determine the Single Side Band (SSB) AM signal $u_{SSB}(t)$ which uses upper sideband. c) Plot the spectrum $U_{SSB}(f)$ of $u_{SSB}(t)$.

Name: q2 40p given the following message and carrier signal mt cos 2000pi t 2cos 6000pi t cos 10000pi t ct 20 cos 320000pi t a determine the hilbert transform of mt b determine the single side ban 00192
Uploaded: 2024-10-29T10:53:45-08:00
Duration: 1 min 36 s
Channel: Anand Jangid
Description: q2 40p given the following message and carrier signal mt cos 2000pi t 2cos 6000pi t cos 10000pi t ct 20 cos 320000pi t a determine the hilbert transform of mt b determine the single side ban 00192

          Q2) [40p] Given the following message and carrier signal
$m(t) = \cos 2000\pi t + 2\cos 6000\pi t + \cos 10000\pi t$
$c(t) = 20 \cos 320000\pi t$
a) Determine the Hilbert transform of $m(t)$.
b) Determine the Single Side Band (SSB) AM signal $u_{SSB}(t)$ which uses upper sideband.
c) Plot the spectrum $U_{SSB}(f)$ of $u_{SSB}(t)$.

q2 40p given the following message and carrier signal mt cos 2000pi t 2cos 6000pi t cos 10000pi t ct 20 cos 320000pi t a determine the hilbert transform of mt b determine the single side ban 00192

Added by Jose Ignacio C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Anand Jangid

10/29/2024

Step 1

The Hilbert transform replaces the cosine terms with sine terms and vice-versa. Therefore, the Hilbert transform of $m(t)$ is: $\hat{m}(t) = \sin 2000\pi t + 2\sin 6000\pi t + \sin 10000\pi t$ Show more…

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Q2) [40p] Given the following message and carrier signal $m(t) = \cos 2000\pi t + 2\cos 6000\pi t + \cos 10000\pi t$ $c(t) = 20 \cos 320000\pi t$ a) Determine the Hilbert transform of $m(t)$. b) Determine the Single Side Band (SSB) AM signal $u_{SSB}(t)$ which uses upper sideband. c) Plot the spectrum $U_{SSB}(f)$ of $u_{SSB}(t)$.