00:01
Hello, here we have to solve the following problem.
00:03
An object has a mass of 10 kilograms and it's a rest of at the top of the incline.
00:11
The incline has a length of 8 meters and the object is allowed to move and it stops on a rough horizontal surface at a distance of 4 meters from the bottom.
00:25
So here the incline plane has a kinetic equation of 0 .4.
00:35
First, in question a, we have to calculate speed of the object at point a.
00:44
Let's do this.
00:45
Let's make a quick sketch.
00:50
When the object is on the incline, it experiences gravity, friction force, and normal reaction.
01:01
Thereby, we should introduce axes, y and x, and here the incline has an angle of theta, which is a 3d4.
01:14
Degree then the initial potential energy plus work of the friction force equals to the kinetic energy at the bottom work of the friction force is negative mu k m g cosine cosine teta times l and the height h is l times times sine theta.
01:56
Therefore, va is square root of 2g.
02:05
L.
02:06
Sin teta minus mu k cosine teta.
02:13
Let's now calculate it...