Q2: F=2500N load is applied to a flat belt - pulley system in order to provide to tighteen the belt as shown in figüre. Diameter of the pulley d= 250 mm ; width of belt b =150mm; thickness of belt: t=5mm, friction factor M=0,3 angle =180\deg and pulley rotates N=1000rpm,=95000(N)/() m^(3)E=70MPa of the belt.
a) What is the maximum power to be transmitted.
b) What is the maximum stress in the belt during the transmitting maksimum power.
(\pi _(1))/(F_(2))<=e^(\mu \theta )
F_(u)=F_(1)-F_(2)
bowers Fu.V
(F_(1))/(b.t)
F_(2)
\sigma _(e)=(t)/(d)E;