00:01
Hi, in this question from the figure we have 5 kilo ohm and 10 kilo ohm resistors are in series.
00:08
Therefore, we have r1 is equal to 15 kilo ohm.
00:13
Then we have 20 kilo ohm, 20 kilo ohm and 1 kilo ohm are in series.
00:23
Therefore, r2 will be equal to 21 kilo ohm.
00:27
Now we have the r1 and r2 are in parallel.
00:33
Therefore, r equivalence will be equal to, so r equivalence is r1 r2 divided by r1 plus r2.
00:42
So, substituting we have this is 8 .6 kilo ohm.
00:46
Now we have 2 kilo ohm resistor is in series with 8 .625 kilo ohm resistor.
00:56
So, this is 625, 8 .625 kilo ohm.
01:05
So therefore, we have, so the resistor will be equal to, so that is rs or r total will be equal to 10 .625 kilo ohm.
01:18
Then we have by ohm's law, so using ohm's law we have p total will be equal to, so from the diagram it is 4 minus 3 that is equal to 1 volt and current i total will be equal to v total by r total that is 1 divided by 10 .625 that is equal to 0 .094 milliampere.
01:43
Now the voltage across the 2 kilo ohm resistor will be equal to current i total, since it is a series resistor the voltage will be same.
01:52
So, 0 .094 into 2 which is equal to 0 .188 volt...