00:01
Hello and welcome to this video solution of numerate.
00:04
Here it's given that the infinite straight wire to the right carries current i1 and this rectangular loop whose long sides are parallel to this wire carrying is current i2.
00:17
Now based on this you have to calculate the magnitude and the direction of the magnetic force on this loop due to the magnetic field of the wire on each side of the loop.
00:28
So a you start by calculating the net force on this loop.
00:38
So now what you have is here if you see here so this is a straight wire and this nearest edge let's say it's one and the other one b2 right the far away loop side of the loop is two let's say.
00:57
Now here you have to remember one concept that when two currents move parallel to each other right they the force between them is attractive right and if in case they are moving the currents are moving opposite then they will be having the repulsive force right.
01:17
So clearly if you see the side one the leftmost side is having current which are parallel right.
01:23
So what you can do is f1 let's say is the force on this left wire which is given by mu naught i1 i2 l over 2 pi r right r is b right.
01:41
So this is what you have as a force between both these wires and okay so this length l will be a right.
01:52
L is the length of this side of the wire right.
01:55
Now here you have to remember the other two sides the one at the top and the bottom will have no force.
02:03
So the next force will be f2 that is on the other side here the force will be repulsive right and this is f1 and here you will be having f2 right...