Q2. The per-phase impedance of a short transmission line is (0.3 + j0.4) ?. The sending-end line-to-line voltage is 3300V, and the load at the receiving end is 330 kilowatts per phase at 0.8 power factor lagging. Calculate (a) the receiving-end voltage and (b) the line current.
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Since the line is short, we can assume that the voltage drop is negligible, so we can approximate the receiving-end voltage as: Vr ≈ Vs = 3300V (b) To calculate the line current, we can use the power formula: P = 3 * Vr * Ir * cos(θ) where P is the power, Vr Show more…
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