Q2. The switch in the figure below opens at t = 0 after having been closed for time immemorial. Find $i_L$ and $i_x$ at (a) t = 0-; (b) t = 0+; (c) t = 0.4 ms.
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The inductor behaves as a short circuit because it has been in a steady state for a long time (time immemorial). Therefore, the current through the inductor is the same as the current provided by the current source, which is 20 mA. Show more…
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