Question

Q2 Vertial plates. \( 0.3 \mathrm{~m} \times 0.3 \mathrm{~m} \) \[ \begin{array}{l} T_{r}=30^{\circ} \mathrm{C}, T_{S}=110^{\circ} \mathrm{C} \quad x \text {-ticher } \\ T_{f}=\frac{30^{\circ} \mathrm{C}+110^{\circ} \mathrm{C}}{2}=70^{\circ} \mathrm{C} \end{array} \] At \( 70^{\circ} \mathrm{C} \); from Air table: \[ \begin{array}{l} K=0.028 \\ P_{r}=0.7 \\ V=2.0 \times 10^{-5} \\ \beta=\frac{1}{T_{4}}(k)=\frac{1}{343}=0.00292 \\ G_{r}=g \beta\left(\frac{T_{4}-T_{5}}{V^{2}}\right) L^{3} \\ R_{a}=G r \cdot G^{2} \\ N_{4}=0.59 R_{a}^{4} \end{array} \]

          Q2
Vertial plates.
\( 0.3 \mathrm{~m} \times 0.3 \mathrm{~m} \)
\[
\begin{array}{l}
T_{r}=30^{\circ} \mathrm{C}, T_{S}=110^{\circ} \mathrm{C} \quad x \text {-ticher } \\
T_{f}=\frac{30^{\circ} \mathrm{C}+110^{\circ} \mathrm{C}}{2}=70^{\circ} \mathrm{C}
\end{array}
\]

At \( 70^{\circ} \mathrm{C} \); from Air table:
\[
\begin{array}{l}
K=0.028 \\
P_{r}=0.7 \\
V=2.0 \times 10^{-5} \\
\beta=\frac{1}{T_{4}}(k)=\frac{1}{343}=0.00292 \\
G_{r}=g \beta\left(\frac{T_{4}-T_{5}}{V^{2}}\right) L^{3} \\
R_{a}=G r \cdot G^{2} \\
N_{4}=0.59 R_{a}^{4}
\end{array}
\]

Q2
Vertial plates.
0.3 m× 0.3 m

Tr=30^∘C, TS=110^∘C x -ticher

Tf=(30^∘C+110^∘C)/(2)=70^∘C

At 70^∘C; from Air table:

K=0.028

Pr=0.7

V=2.0 × 10^-5
β=(1)/(T4)(k)=(1)/(343)=0.00292

Gr=g β((T4-T5)/(V^2)) L^3

Ra=G r · G^2

N4=0.59 Ra^4

Added by Karen F.

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