00:01
This problem wants us to find the gradient of the line, the equation of line, and an equation of the perpendicular line that passes through point p, which is noted here.
00:08
And to be able to find the gradient of the line, we can look at two points we know our line is traveling through.
00:13
First, with point p, which is 5 -0.
00:16
And we can also focus on the y intercept, which looks to be 0 .4.
00:19
And we can find the gradient or the slope by looking at the rise of a run value.
00:23
And it looks like we rise or fall four units, so that's minus 4.
00:28
And then we run 5 to the right or increase to the right 5 units.
00:32
So that is a negative 4 of a positive 5, which would give us a gradient of negative 4 -fifths.
00:37
And to write our equation, we'll write it in the slope intercept form, which is y -ex plus b.
00:42
And we just found the slope of the gradient, which is m, so that would be negative 4 -fist.
00:47
And our b value would be ry intercept, and we already saw that that was 0 ,4...