Q2/Consider a cylindrical nickel wire 2.0 mm (0.08 in.) in diameter and 3x10^3 mm (1200 in.) long. Calculate its elongation when a load of 300 N (67 lb) is applied. Assume that the deformation is totally elastic.
Added by Kelly G.
Step 1
First, we need to find the cross-sectional area (A) of the wire. The wire has a diameter of 2.0 mm, so the radius (r) is 1.0 mm. The cross-sectional area of a cylinder is given by the formula A = πr^2. A = π(1.0 mm)^2 = π mm^2 Show more…
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