Question

A centrifugal compressor takes in 480m³ of gas per minute at a temperature of T1 and pressure of P1 and delivers it at a pressure of 350 KPa. Compression takes place according to the law $pV^{1.4} = c$ and the input power is 920kW. Determine: a. The mass flow rate of the gas, m b. The output volume rate, V2 c. The output temperature, T2 d. The heat transfer rate, Q and e. The thermal efficiency of the compressor, $\eta$ Take $C_p = 1150 \text{ JKg}^{-1}K^{-1}$ and $C_v = 650 \text{ JKg}^{-1}K^{-1}$

          A centrifugal compressor takes in 480m³ of gas per minute at a
temperature of T1 and pressure of P1 and delivers it at a pressure of 350
KPa. Compression takes place according to the law $pV^{1.4} = c$ and the input
power is 920kW. Determine:
a. The mass flow rate of the gas, m
b. The output volume rate, V2
c. The output temperature, T2
d. The heat transfer rate, Q and
e. The thermal efficiency of the compressor, $\eta$
Take $C_p = 1150 \text{ JKg}^{-1}K^{-1}$ and $C_v = 650 \text{ JKg}^{-1}K^{-1}$

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A centrifugal compressor takes in 480m³ of gas per minute at a
temperature of T1 and pressure of P1 and delivers it at a pressure of 350
KPa. Compression takes place according to the law pV^1.4 = c and the input
power is 920kW. Determine:
a. The mass flow rate of the gas, m
b. The output volume rate, V2
c. The output temperature, T2
d. The heat transfer rate, Q and
e. The thermal efficiency of the compressor, η
Take Cp = 1150 JKg^-1K^-1 and Cv = 650 JKg^-1K^-1

Added by Jennifer O.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

10/13/2023

Step 1

4 = c First, we need to convert the volume flow rate from m^3/min to m^3/s: V1 = 480 m^3/min = 480/60 m^3/s = 8 m^3/s Next, we can calculate the mass flow rate using the ideal gas equation: PV = mRT m = PV / RT m = P1V1 / RT1 m = (160 * 10^3 Pa) * 8 m^3 / (8.314 Show more…

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Q3. A centrifugal compressor takes in 480m^3 of gas per minute at a temperature of T1 and pressure of P1 and delivers it at a pressure of 350 KPa. Compression takes place according to the law pV^1.4 = c and the input power is 920 kW. Determine: a. The mass flow rate of the gas, m b. The output volume rate, V2 c. The output temperature, T2 d. The heat transfer rate, Q and e. The thermal efficiency of the compressor, η Take Cp = 1150 Jkg^(-1)K^(-1) and Cv = 650 Jkg^(-1)K^(-1) T1 = 16°C P1 = 160 kPa

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