00:01
In the question we have given open loop transfer function and that is gh of s is equal to k s square minus 8 s plus 15 upon s square plus 3 s plus 2.
00:21
So from here we can further write this as k s minus 5 multiplied by s minus 3 upon s plus 1 multiplied by s plus 2.
00:38
So here we have number of poles that is p is equal to 2 and we have number of zeros that is z is equal to 2.
00:53
Now we know that asymptote that is a is equal to p minus z so a will be equal to 2 minus 2 which is equal to 0.
01:05
So therefore angle of asymptote that is angle a will be equal to 2 alpha plus 1 multiplied by 180 upon p minus z.
01:19
Since we can see that p is equal to z so angle of asymptote does not exist because p and z are equal.
01:36
So here we have j omega and here we have sigma and here we will have 3 and here we will have 5 and here we will have minus 1 and here we will have minus 2.
01:53
Now we will find centroid.
01:58
So centroid we have the formula of centroid that is summation of real part of pole minus summation of real part of 0 upon p minus 0.
02:10
So again we have p is equal to 0 so hence we can say that hence therefore centroid does not exist.
02:23
Now we will find break point.
02:31
So for the break point we have 1 plus g of gh of s is equal to 0...