00:01
Hello students, in this question given as a applied voltage is equal to 1 .875°.
00:08
So, this will be equal to the 1 .8 in bracket cos of 75 degree plus j sine of 75 degree.
00:21
So, after calculation we will get the voltage is 1 .7 minus 0 .7 j and the complex frequency is given as minus 2 plus 1 .5 j per second and the capacitance is given as 250 milli farad.
00:51
In the first part of the question we have to calculate the current in the frequency domain representation.
00:58
So, this is given as is is equal to in the frequency domain representation is equal to v by t, v by 2 and plus c capacitance as frequency v is the voltage.
01:12
Now we will v by 2.
01:15
Write here 0 .85 minus 0 .35 j plus the value of c is 20 .25 farad in bracket.
01:40
The value of s is minus 2 .1 .5 j and in another bracket the value of v voltage is 1 .7 minus 0 .7 j.
02:04
After calculation we will get current in the frequency domain is equal to 0 .25 plus 0 .65 j.
02:23
Now we have to write in another form.
02:26
We will write here the magnitude of this current will be is equal to under root 0 .25 whole square plus 0 .65 whole square.
02:39
Then we will get the amplitude magnitude of the current which is 0 .67 ampere and the angle is represent the sin theta and this is represent the cos theta.
02:52
So tan theta will be equal to the 0 .65 upon 0 .25...