00:02
All right.
00:03
So this takes a bit of time to parse through.
00:07
So i've left the results up so you can get those right away.
00:13
But i'll just walk you through the process that i used.
00:16
Now, the first thing i did was i redrew the circuit to have it make a little bit more sense.
00:22
So i arranged it linearly across like this.
00:25
And then i found the equivalent resistances in each little part.
00:30
So looking at it.
00:32
At this part here i started here.
00:35
This is resistor three and resistor four.
00:38
And when we combine those, we use the one overrule.
00:40
We're going to get a total resistance for them of 11 .87 oms.
00:47
And then we can combine that total resistance with six and seven.
00:51
So i label that r three, four, six, seven.
00:55
And that we just add the resistances of six and seven to it.
00:59
And we get 128 .87 oms for that part right here.
01:04
And then to get three through seven, to get five on there, we do the one over rule again.
01:10
So one over 128 plus one over 153, and then take the reciprocal.
01:16
We get 69 .95 oms, which runs up to 70.
01:22
And that gives us three through seven.
01:26
And then to get one, two, added in there, we just add those two.
01:31
To it so add 13 and 64 you get 146 .95 and then to get the 11 we do the one over rule again so one over this plus one over 11 which is a thousand which you can see right here and we get this as the equivalent resistance of this whole pocket right here next i did the same thing over here this one's quite a bit simpler it's just nine and 10 you add together to get one 10 because they're 42 and 8, or excuse me, 83 and 27.
02:04
And then 8 through 10, we do the one over rule.
02:07
So 1 over 110 plus 1 over 42.
02:10
And then take the reciprocal and we get 30 .39.
02:13
And then to get the equivalent resistance of the entire circuit, you add this and this and we get 158 .52, which is exactly what was given in the table.
02:24
So that shows that we're on the right track.
02:26
Next, the voltage at a was given to us.
02:30
As 480.
02:30
That's the voltage difference through the whole circuit.
02:34
So at h, we should have zero volts left.
02:37
We can find the current at a and h by taking the current through the whole circuit.
02:44
So 480 divided by the equivalent resistance in the entire circuit.
02:47
And we get 3, or 3 .03 or something like that, which i rounded to 3.
02:54
And then i kind of worked my way backwards.
02:56
So i know the equivalent resistance here and the point at f may as well be at this point right here and so that means the current through or the the potential difference or the potential the electric potential the voltage at point f is going to be the same as this point right here that's the current will be different since f is beyond the split but the voltage here will be the same as the voltage here because there's no resistance in between.
03:28
So taking this equivalent resistance, i can find the voltage drop across here to be 92 volts, which means the voltage at f is also 92 volts.
03:40
And then i can find the current through resistor 8 by taking that voltage over resistance to get the current at f to be 2 .2.
03:51
Likewise, i can do a similar thing here.
03:53
The voltage drop at across 9 and 10 will be 92.
03:58
And so i can find the current using the equivalent resistance of 110 to find the current at g to be 0 .8...