Question

Q4. The currents in a $\Delta$-connected load are: $I_{ab} = 10\angle 0^\circ A$, $I_{bc} = 20\angle -90^\circ A$ and $I_{ca} = 15\angle 90^\circ A$. Find the line currents ($I_a$, $I_b$ and $I_c$). Also determine the symmetrical components of the phase and line currents.

Name: q4 the currents in a delta connected load are iab 10angle 0circ a ibc 20angle 90circ a and ica 15angle 90circ a find the line currents ia ib and ic also determine the symmetrical compo 19073
Uploaded: 2023-12-12T00:24:41-08:00
Duration: 2 min 36 s
Channel: Supreeta N
Description: q4 the currents in a delta connected load are iab 10angle 0circ a ibc 20angle 90circ a and ica 15angle 90circ a find the line currents ia ib and ic also determine the symmetrical compo 19073

          Q4. The currents in a $\Delta$-connected load are: $I_{ab} = 10\angle 0^\circ A$, $I_{bc} = 20\angle -90^\circ A$ and $I_{ca} = 15\angle 90^\circ A$. Find the line currents ($I_a$, $I_b$ and $I_c$). Also determine the symmetrical components of the phase and line currents.

q4 the currents in a delta connected load are iab 10angle 0circ a ibc 20angle 90circ a and ica 15angle 90circ a find the line currents ia ib and ic also determine the symmetrical compo 19073

Added by Michael H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

12/12/2023

Step 1

03\angle -56.31^\circ A$ $I_b = 20\angle -90^\circ - 10\angle 0^\circ = -j20 - 10 = 22.36\angle -116.57^\circ A$ $I_c = 15\angle 90^\circ - 20\angle -90^\circ = j15 + j20 = j35 = 35\angle 90^\circ A$ Show more…

Show all steps

Thanks for your feedback!

Q4. The currents in a $\Delta$-connected load are: $I_{ab} = 10\angle 0^\circ A$, $I_{bc} = 20\angle -90^\circ A$ and $I_{ca} = 15\angle 90^\circ A$. Find the line currents ($I_a$, $I_b$ and $I_c$). Also determine the symmetrical components of the phase and line currents.