Q4(a) [12.5 Marks] For ethanol, \( \Delta \mathrm{vapH}^{0}=43.5 \mathrm{~kJ} \mathrm{~mol}^{-1} \). (i) Calculate q, w, \( \Delta \mathrm{H} \) and \( \Delta \mathrm{U} \) when \( 1.75 \mathrm{~mol}_{2} \mathrm{H}_{5} \mathrm{OH}(\mathrm{I}) \) is vaporised at \( 260 \mathrm{~K} \) at constant external pressure. (ii) Predict whether the vaporisation of ethanol is exothermic or endothermic. (iii) If methanol has a \( \Delta_{\mathrm{vap}} \mathrm{H}^{0}=37.4 \mathrm{~kJ} \mathrm{~mol}^{-1} \), would you expect methanol or ethanol to have greater intermolecular forces? Give a reason for your answer. (iv) Explain why the heat transferred and work done on a system are path functions and not state functions.
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So, q = 1.75 mol * 43.5 kJ/mol = 76.125 kJ. The work done (w) during the vaporization can be calculated using the formula w = -PΔV. However, since the volume change during vaporization is not given, we cannot calculate the work done. The change in enthalpy (ΔH) Show more…
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