Question

Q5. The formation constant (Kf) for HgI42-complex is 7.65 x 1025 which corresponds to the equilibrium: Hg2+(aq) + 4I-(aq) ? HgI42-(aq) What is the concentration of the remaining free Hg2+ ions in 500.0 mL of a solution that was originally 0.010 M of Hg2+ and 0.78 M of I-ions? A) 4.41 x 10-28 M B) 3.33 x 10-32 M C) 1.79 x 10-28 M D) 8.97 x 10-33 M

          Q5. The formation constant (Kf) for HgI42-complex is 7.65 x 1025 which corresponds to the equilibrium:

Hg2+(aq) + 4I-(aq) ? HgI42-(aq)

What is the concentration of the remaining free Hg2+ ions in 500.0 mL of a solution that was originally 0.010 M of Hg2+ and 0.78 M of I-ions?

A) 4.41 x 10-28 M
B) 3.33 x 10-32 M
C) 1.79 x 10-28 M
D) 8.97 x 10-33 M

Q5. The formation constant (Kf) for HgI42-complex is 7.65 x 1025 which corresponds to the equilibrium:

Hg2+(aq) + 4I-(aq) ? HgI42-(aq)

What is the concentration of the remaining free Hg2+ ions in 500.0 mL of a solution that was originally 0.010 M of Hg2+ and 0.78 M of I-ions?

A) 4.41 x 10-28 M
B) 3.33 x 10-32 M
C) 1.79 x 10-28 M
D) 8.97 x 10-33 M

Added by Abdullahbioe -.

Chemical Principle

Steven S. Zumdahl, Donald J. DeCoste 7th Edition

Chapter 8

Instant Answer

Solved by Expert David Collins

03/19/2024

Step 1

We are given the formation constant (\(K_{\mathrm{f}}\)) for the complex ion \( \mathrm{HgI}_{4}^{2-} \) as \( 7.65 \times 10^{25} \). The reaction is: \[ \mathrm{Hg}^{2+}(aq) + 4 \mathrm{I}^{-}(aq) \rightleftharpoons \mathrm{HgI}_{4}^{2-}(aq) \] We need to find Show more…

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