00:01
So, by reading this question, we will draw the first simple circuit.
00:04
Let's draw it.
00:15
This is a kind of a circuit we have and we will put the values.
00:22
This is 20, this is j30, okay this is plus, this is minus and here it is vr which is 33 kv and after that this is vs.
00:37
So let's go ahead.
00:38
We have the value of vr which is 70 mw.
00:45
After that power factor that is we have this cos phi and that's equal to 0 .85 and now we go ahead that is p and that's equal to 3 vph iph multiplied by cos phi and p which is 70 mw which is 10 to the power of 6 and that's equal to 3 multiplied by 33 multiplied by 10 to the power of 3 which is v.
01:21
After that we have iph which is unknown.
01:25
From here the cos phi which is 0 .85.
01:30
So, from here we will get this iph value which is current and that is 831 .85 a.
01:39
Now we will go ahead that phase angle.
01:43
So, this phase angle that's equal to cos inverse 0 .85.
01:51
That means from here we will get the angle which is 31 .79 degree.
01:58
This is it.
01:59
Now we will go ahead that iph is equal to 831 .85 angle of minus 31 .79 degree...