Q7. Upon treatment with a strong base (such as NaOH), 2-naphthol is converted to its conjugate base which is then further reacted with n-butyl iodide to afford a product. Draw the reaction sequences including mechanism.

Name: Q7. Upon treatment with a strong base (such as NaOH), 2-naphthol is converted to its conjugate base which is then further reacted with n-butyl iodide to afford a product. Draw the reaction sequences including mechanism.
Uploaded: 2022-10-12T03:22:30-08:00
Duration: 2 min 14 s
Channel: Adi S
Description: Q7. Upon treatment with a strong base (such as NaOH), 2-naphthol is converted to its conjugate base which is then further reacted with n-butyl iodide to afford a product. Draw the reaction sequences including mechanism.

          Q7. Upon treatment with a strong base (such as NaOH), 2-naphthol is converted to its conjugate base which is then further reacted with n-butyl iodide to afford a product. Draw the reaction sequences including mechanism.

Q7. Upon treatment with a strong base (such as NaOH), 2-naphthol is converted to its conjugate base which is then further reacted with n-butyl iodide to afford a product. Draw the reaction sequences including mechanism.

Added by Bradley P.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

10/12/2022

Step 1

2-naphthol is a weak acid due to the phenolic hydroxyl group (-OH). The base will deprotonate the hydroxyl group, forming the conjugate base, a naphthoxide ion. Show more…

Show all steps

Thanks for your feedback!

Q7. Upon treatment with a strong base (such as NaOH), 2-naphthol is converted to its conjugate base which is then further reacted with n-butyl iodide to afford a product. Draw the reaction sequences including mechanism.