The \( \mathrm{R} \) isomer of limonene has an optical rotation, alpha, of \( +123^{\wedge} \) Icirc the \( \mathrm{S} \) isomer has an optical rotation, alpha, of \( -123^{\wedge} \) |circ. If the observed rotation of a mixture of the \( \mathrm{R} \) and \( S \) isomer resulted in an alpha of \( 109 \wedge \) circ, what are the percentages of Question:
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Let x be the percentage of the R isomer and y be the percentage of the S isomer. Since there are only two isomers in the mixture, their percentages must add up to 100%. Therefore, we have: x + y = 100% ...(1) Show more…
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