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Crisel E.

Algebra and Trigonometry

6 days, 4 hours ago

Find $a_{1}$ and $d$ for each arithmetic sequence. $$S_{20}=1090, a_{20}=102$$

Chapter 8

Further Topics in Algebra

Section 2

Arithmetic Sequences and Series

S 20, that is 190 and a 20 that is 20 term, is 102. Now what we? What we know is that s n some of men, tom, has a formula n by 2. A plus l here a is the first term, so we will write it as a 1. Now this s n is nothing but 10904 is equal to 20 point, so it becomes 20 divided by 2 and 1 will have to find. Plus. L is the last term, so 28 terms, 102. Now moving ahead, this becomes 1090 multiplied by 2. Divided by 20 is equal to a 1 plus 102 point, and if you solve it, we get your 109. Minus 102 is equal to a 1, and this implies a 1 is equal to nothing but 7. So a 1 is equal to 7 and we need to find d for d will go with a 20 equals to 102 point. This implies a 20 can be written as a plus 19 d and it is equal to 102 point because we know, and tom is equal to a plus and minus 1 d. So by using the same formula- and this is a 1. So a 1 is 7 plus 19 d is equal to 102 point, and this implies 19 d comes out to be, as here comes 95 and d is nothing but 5, so d is 5 and a 1 is 7.

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