(10 points) A \( 50.0 \mathrm{~kg} \) pole vaulter running at \( 7.0 \mathrm{~m} \) /s reaches a height of \( 5.05 \mathrm{~m} \) to clear a 5-m-high bar. Neglect air resistance and the energy absorbed by the pole. Determine her, speed when she is above the bar.
Added by Kien Z.
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Step 1
First, we need to find the initial kinetic energy of the pole vaulter when she is running on the ground. The formula for kinetic energy is: \(KE = \frac{1}{2}mv^2\) where \(m\) is the mass of the pole vaulter and \(v\) is her speed. Show more…
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