I. Torque 1. A force is being applied on a machine given by the vector \( \vec{F}=10 N \hat{\imath}-5 N \hat{\jmath} \). The position vector from the axis of rotation to the point where the force is applied is \( \hat{r}=-0.5 \mathrm{mi}+0.5 \mathrm{~m} \hat{\jmath} \). a. Sketch the force vector, the position vector and the origin on a cartesian plane. b. Determine the direction of the torque using the right-hand rule. c. What is the torque vector produced by this force? 2. A \( 300.0-\mathrm{N} \) sign hangs from the end of a uniform strut. The strut is \( 4.0 \mathrm{~m} \) long and weighs \( 500.0 \mathrm{~N} \). The strut is supported by a hinge at the wall and by a cable whose other end is tied to the wall at a point \( 3.0 \mathrm{~m} \) above the left end of the strut.
Added by Kyle M.
Close
Step 1
To sketch the force vector, position vector, and origin on a Cartesian plane, we can represent the force vector as an arrow pointing from the origin to the point (10, -5). The position vector can be represented as an arrow pointing from the origin to the point Show more…
Show all steps
Your feedback will help us improve your experience
Christian Dell and 57 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
One force acting on a machine part is $\overrightarrow{F} = (-5.00 N)\hat{\imath} + (4.00 N)\hat{\jmath}$. The vector from the origin to the point where the force is applied is $\overrightarrow{r} = (-0.450 m)\hat{\imath} + (0.150 m)\hat{\jmath}$. (a) In a sketch,show $\overrightarrow{r}, \overrightarrow{F},$ and the origin. (b) Use the right-hand rule to determine the direction of the torque. (c) Calculate the vector torque for an axis at the origin produced by this force. Verify that the direction of the torque is the same as you obtained in part (b).
Dynamics of Rotational Motion
Torque
One force acting on a machine part is $\vec{\boldsymbol{F}}=(-5.00 \mathrm{N}) \hat{\imath}+$ $(4.00 \mathrm{N}) \hat{\boldsymbol{J}}$ . The vector from the origin to the point where the force is applied is $\vec{r}=(-0.450 \mathrm{m}) \hat{\imath}+(0.150 \mathrm{m}) \hat{\boldsymbol{J}}$ (a) In a sketch, show $\vec{r}, \vec{\boldsymbol{F}},$ and the origin. (b) Use the right-hand rule to determine the direction of the torque. (c) Calculate the vector torque for an axis at the origin produced by this force. Verify that the direction of the torque is the same as you obtained in part (b).
One force acting on a machine part is $\overrightarrow{\boldsymbol{F}}=(-5.00 \mathrm{N}) \hat{\boldsymbol{\imath}}+$ $(4.00 \mathrm{N}) \hat{\jmath}$ . The vector from the origin to the point where the force is applied is $\vec{r}=(-0.450 \mathrm{m}) \hat{\imath}+(0.150 \mathrm{m}) \hat{\jmath} .$ (a) In a sketch, show $\vec{r}, \vec{F},$ and the origin. (b) Use the right-hand rule to determine the direction of the torque. (c) Calculate the vector torque produced by this force. Verify that the direction of the torque is the same as you obtained in part (b).
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Watch the video solution with this free unlock.
EMAIL
PASSWORD