Question

Q1. The following equation represents the diazonium ion diazotate oxide ion equilibrium: - +\\ K Ar-N$_2^+$ + H$_2$O $\rightleftharpoons$ Ar-N=N-O$^-$ + 2H$^+$ Some values of pk for substituted benzene diazo compounds at 25 $^\circ$C are the following; p-NO$_2$ 9.44, m-Cl 10.7, H 11.9, m-CH$_3$ 12.12. Plot these values against $\sigma$ for this equilibrium. Does the $\rho$ have the sign you would have expected? Why? [2 Marks] $\sigma$ values: NO$_2$ $\sigma_m$ = 0.71 $\sigma_p$ = 0.778 Cl $\sigma_m$ = 0.373 $\sigma_p$ = 0.227 CH$_3$ $\sigma_m$ = -0.069 $\sigma_p$ = -0.17

          Q1. The following equation represents the diazonium ion diazotate oxide ion
equilibrium: -
+\\
K
Ar-N$_2^+$ + H$_2$O $\rightleftharpoons$ Ar-N=N-O$^-$ + 2H$^+$
Some values of pk for substituted benzene diazo compounds at 25 $^\circ$C are the following;
p-NO$_2$ 9.44, m-Cl 10.7, H 11.9, m-CH$_3$ 12.12. Plot these values against $\sigma$ for this
equilibrium. Does the $\rho$ have the sign you would have expected? Why? [2 Marks]
$\sigma$ values:
NO$_2$ $\sigma_m$ = 0.71
$\sigma_p$ = 0.778
Cl
$\sigma_m$ = 0.373
$\sigma_p$ = 0.227
CH$_3$ $\sigma_m$ = -0.069
$\sigma_p$ = -0.17

Q1. The following equation represents the diazonium ion diazotate oxide ion
equilibrium: -
+

K
Ar-N2^+ + H2O ⇌ Ar-N=N-O^- + 2H^+
Some values of pk for substituted benzene diazo compounds at 25 ^∘C are the following;
p-NO2 9.44, m-Cl 10.7, H 11.9, m-CH3 12.12. Plot these values against σ for this
equilibrium. Does the ρ have the sign you would have expected? Why? [2 Marks]
σ values:
NO2 = 0.71
= 0.778
Cl
= 0.373
= 0.227
CH3 = -0.069
= -0.17

Added by Shawn G.

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