Question

Quadrilateral ABCD is shown on the coordinate plane below. Complete the proof that ABCD is a parallelogram. Using the distance formula, AD = ?((-7 - (-6))² + (1 - 5)²) . Also, BC = . Both AD and BC are equal to , which means AD ? BC. Also using the distance formula, AB = and DC = ?((1 - (-7))² + (-2 - 1)²) . Both AB and DC are equal to , which means AB ? DC. So, since ABCD is a parallelogram.

          Quadrilateral ABCD is shown on the coordinate plane below.
Complete the proof that ABCD is a parallelogram.
Using the distance formula,
AD = ?((-7 - (-6))² + (1 - 5)²) . Also,
BC = . Both
AD and BC are equal to , which
means AD ? BC.
Also using the distance formula,
AB = and
DC = ?((1 - (-7))² + (-2 - 1)²) . Both AB and
DC are equal to , which means
AB ? DC. So, since
ABCD is a parallelogram.

Quadrilateral ABCD is shown on the coordinate plane below.
Complete the proof that ABCD is a parallelogram.
Using the distance formula,
AD = ?((-7 - (-6))² + (1 - 5)²) . Also,
BC = . Both
AD and BC are equal to , which
means AD ? BC.
Also using the distance formula,
AB = and
DC = ?((1 - (-7))² + (-2 - 1)²) . Both AB and
DC are equal to , which means
AB ? DC. So, since
ABCD is a parallelogram.

Added by Randy C.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

Instant Answer

Solved by Expert Scott Mcclendon

03/28/2023

Step 1

Let's assume the coordinates of the vertices are as follows: A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4). Show more…

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Quadrilateral ABCD is shown on the coordinate plane below. Complete the proof that ABCD is a parallelogram. Using the distance formula, AD = sqrt((-7 - (-6))^2 + (1 - 5)^2). Also, BC = Both AD and BC are equal to which means AD is congruent to BC. Also using the distance formula, AB = and DC = sqrt((1 - (-7))^2 + (-2 - 1)^2). Both AB and DC are equal to which means AB is congruent to DC. So, since ABCD is a parallelogram.