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Question 03: Consider the model shown below that applied in the case of a pnp transistor whose base is grounded, the emitter is fed by a constant-current source that supplies a 2-mA current into the emitter terminal, and the collector is connected to a -10V dc supply. Find the emitter voltage, the base current, and the collector current if for this transistor $eta$=50 and $I_s = 10^{-14}$A.

          Question 03: Consider the model shown below that applied in the case of a pnp transistor whose base is grounded, the emitter is fed by a constant-current source that supplies a 2-mA current into the emitter terminal, and the collector is connected to a -10V dc supply. Find the emitter voltage, the base current, and the collector current if for this transistor $eta$=50 and $I_s = 10^{-14}$A.

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Question 03: Consider the model shown below that applied in the case of a pnp transistor whose base is grounded, the emitter is fed by a constant-current source that supplies a 2-mA current into the emitter terminal, and the collector is connected to a -10V dc supply. Find the emitter voltage, the base current, and the collector current if for this transistor eta=50 and Is = 10^-14A.

Added by Beatriz M.

Master Resource Book in JEE Main Physics

D. B. Singh 1st Edition

Chapter 26

Instant Answer

Solved by Expert Supreeta N

05/18/2023

Step 1

The emitter current (Ie) is given as 2mA. We know that the emitter current is the sum of the base current (Ib) and the collector current (Ic). We also know that the base current is much smaller than the collector current in a transistor, so we can approximate Show more…

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Transcript

00:01 Hello students, in this question a model shown that a pnb transistor whose base is grounded, so the emitter is fed by constant current source.

00:11 So given that emitter current ie is equal to 2 milliampere and the emitter current, collector current ic is equal to beta times ib, right? so we are given that beta is equal to 250 and is is equal to 10 to the power minus 14, right? now first we can calculate the emitter voltage vbe.

00:50 So since base is grounded, the emitter voltage will be equal to the voltage across the constant current source.

00:57 That is vbe will be equal to v of the source.

01:07 So that is given, it is connected to a 10 volt supply.

01:12 So that is equal to 10 volt.

01:15 Okay, that is the first part.

01:17 Now the second part is to find the base current ib.

01:22 So ib, you can use the equation ie is equal to, right? ie, you can use that the equation for emitter current is there.

01:37 So emitter current equation ie is equal to is times e raised to vbe by vt minus 1.

01:47 So we can use that equation to find out.

01:53 So 2 milliampere is equal to is times e raised to vbe is equal to 10 divided by vt.

02:08 So vt is also equal to vbe.

02:14 So that is 10 minus 1.

02:16 So you will get is times 2 .71 minus 1...

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