00:01
So here we are considering the circuit which is shown here.
00:03
So this is the circuit where the resistor r1 is given that is of 3 ohm from here and another resistor of r2 is connected which is equals to r1 that is equals to 1 ohm and here a resistor r3 is connected which is equals to 4 ohm.
00:18
Then from here we are given a battery which is connected from here with voltage that is equals to 3 volt and from here a resistor r1 is connected that is of 2 ohm and from here we are again given the battery source from here.
00:33
So this is 2 ampere current passing from this point this is point c this is point b this is point a from here.
00:40
So here we have to calculate the voltage across the circuit source that is we have to find out the value of c of v of cg.
00:51
So this is what we need to find out.
00:54
Now here for finding this value we are considering about the rth voltage that is r of ab.
00:59
So r of ab from here is equals to 3 ohm plus 4 ohm which is in parallel to 2 ohm.
01:05
Solving this here so we get the value of r of ab that is equals to 14 divided by the 9 ohm.
01:11
Now we are considering about the norton's current through this branch ab.
01:18
So norton current from the branch ab is given as i that is equals to 3 volt divided by the 2 ohm 3 minus v of c which is divided by 4.
01:27
So solving the term from here plug into the values so 2 vc minus 3 divided by 4 plus vc minus 3 divided by 3.
01:35
Solving the term from here we get the value of vc that become equals to 5 volt.
01:40
Now again i is equals to 3 of v divided by the 2 ohm plus 3v minus 5v which is divided by 4 ohm...